Physics High School

## Answers

**Answer 1**

In a **fission reaction,** the reactants are typically two or more atoms of a heavy element, such as uranium.

What is fusion reaction?

Fusion reaction is the process of combining two atomic nuclei to form a single, larger nucleus. This process releases a large amount of **energy**, which can be harnessed to generate electricity or to power spacecraft. Fusion reactions occur naturally in stars, and scientists have been trying to replicate the process on Earth for decades. In a fusion reaction, two atomic nuclei are fused together at extremely high temperatures, forming a single, larger nucleus, and releasing a large amount of energy in the process.

When these **atoms** collide, they break apart, releasing large amounts of energy in the form of gamma radiation. In contrast, the reactants in a fusion reaction are typically two or more small atoms such as hydrogen. When these atoms come together, they fuse, releasing even larger amounts of energy in the form of gamma radiation. The energy released in a fusion reaction is much greater than that of a fission reaction.

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## Related Questions

The graph above shows the force exerted by a spring as a function of the length of the spring. A block on a frictionless table is pushed against the spring that is fastened to a wall. The spring is compressed until its length is 20 cm. The block is then released. Which of the following values is closest to the kinetic energy with which the block leaves the spring?

### Answers

The **kinetic energy** of the **spring **is obtained as 12 J. Option C

What is the kinetic energy of the spring?

We know that the kinetic energy is the energy that is required to stretch the spring. We can use the **graph **that has been shown to show the force constant of the spring.

We can find the** force constant **as the slope of the graph as follows;

K = [tex]y_{2} - y_{1} /x_{2} - x_{1}[/tex]

K = 60 - 0/0.3 - 0.2

K = 60/0.1

K = 600 N/m

We then have;

W = KE = 1/2 Kx^2

Thus;

KE = 0.5 * 600 * (20 * 10^-2)^2

KE = 12 J

It would have a kinetic energy of 12 J.

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If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects.

### Answers

**Answer:**

decrease

**Explanation:**

as objects of equal mass become farther, the gravitational force between them weakens

as you stand near a railroad track, a train passes by at a speed of 33.5 m/s33.5 m/s while sounding its horn at a frequency of 219 hz.219 hz. what frequency do you hear as the train approaches you? what frequency do you hear while it recedes? use 342 m/s342 m/s for the speed of sound in air.

### Answers

frequency as the train approaches is = **236.6 hz, **frequency while it recedes is = **195.3 hz .**

How quickly does sound travel across water and air?

In contrast to air, sound travels more quickly in water.Under normal circ*mstances, the speed of sound is around 343 m / sec, while the sound speed in water is approximately 1,480 m / sec.

From whence does Mach 1 originate?

In a speech given in Zurich in 1929, Swiss scientist Jakob Ackeret suggested the use and naming of Mach numbers.Ackeret gave the number Ernst Mach's name after the physicist, who in 1887 experimented by taking a photograph of a moving object faster than the rate of sound.

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Correctly label the following anatomical features of the semicircular ducts. Cupula Supporting tells Vestibular braneh CN Hair cells Crista ampullaris BEDRE Endolymph

### Answers

Cupula: The cupula is a gelatinous structure that is attached to the sensory hair cells in the semicircular ducts.

Supporting tells: The supporting tells are the structures that support and anchor the cupula in the semicircular ducts.

Vestibular braneh: The vestibular branch is a branch of the vestibulocochlear nerve (CN VIII) that carries sensory information from the semicircular ducts to the brain.

CN: CN stands for cranial nerve, which is a group of nerves that originate in the brain and innervate various parts of the head and neck. In this context, CN VIII refers to the vestibulocochlear nerve.

Hair cells: Hair cells are sensory cells that are located in the semicircular ducts and are responsible for detecting changes in angular acceleration.

Crista ampullaris: The crista ampullaris is a ridge of sensory hair cells that is located in the ampulla of the semicircular ducts.

BEDRE: It is not clear what "BEDRE" refers to in this context. Please provide more context or clarify the term.

Endolymph: Endolymph is a fluid that is found within the inner ear and is responsible for transmitting sound and movement information to the brain. It is located within the semicircular ducts and other parts of the inner ear.

what frequency would a 1.6-ft-long nylon string that has a thickness of 3/32 in produce (a) if put under an equal tension? (b) if put under one-third of the original tension?

### Answers

a) The **frequency** would a 1.6-ft-long nylon string that has a thickness of 3/32 in produce if put under an equal tension is 3.74 x [tex]10^{-5}[/tex] kg/m.

b) The frequency would a 1.6-ft-long nylon string that has a thickness of 3/32 in produce if put under one-third of the original tension is 0.577.

The frequency of a string under tension is given by the equation f = (1 / 2L) × √(T / mu)

where f is the frequency, L is the length of the string, T is the** tension **in the string, and mu is the linear mass density of the string.

To calculate the frequency of a 1.6-ft-long nylon string with a thickness of 3/32 in, we need to first determine the linear mass density of the string. The linear mass density of a string is given by the formula:

mu = (m / L) = (p × A) / L

where mu is the **linear mass density**, m is the mass of the string, p is the density of the material of the string, A is the cross-sectional area of the string, and L is the length of the string.

The density of nylon is approximately 1.15 g/cm^3, and the cross-sectional area of the string can be calculated from its thickness:

A = (3/32 in)² × pi = 0.0293 in²

Converting the length of the string to inches, we get:

L = 1.6 ft × 12 in/ft = 19.2 in

Substituting these values into the equation for linear mass density, we get mu = (1.15 g/cm³ × 0.0293 in²) / 19.2 in = 0.00146 g/in

Converting this to the units used in the frequency equation, we get mu = 0.00146 g/in × 1 kg/1000 g × 1 m/39.37 in = 3.74 x [tex]10^{-5}[/tex] kg/m

Now that we have calculated the linear mass density of the string, we can use the frequency equation to determine the frequency of the string under different tensions.

(a) If the string is put under equal tension, the frequency is given by f = (1 / 2L)

b) The original tension in the string is T and the string is put under a tension of T/3, the frequency will be reduced by a factor of √(1/3) = 0.577, or about 58% of the original frequency.

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electrons accelerated from rest through a 63.6 kv potential difference strike a tungsten target, causing it to emit x-rays. what is the shortest wavelength (in nm) of radiation emitted by the target?

### Answers

The shortest **wavelength** of radiation emitted by the tungsten target is 187 nm.

The shortest wavelength of **radiation emitted** by the tungsten target is determined by the energy of the electrons that strike the target. The energy of the electrons can be calculated using the equation:

E = qV

where E is the energy of the **electrons**, q is the charge of the electrons (1.60 x [tex]10^{-19}[/tex] C), and V is the potential difference through which the electrons are accelerated.

In this case, V = 63.6 kV = 63.6 x [tex]10^3[/tex] V, so the energy of the electrons is:

E = 1.60 x [tex]10^{-19}[/tex] C * 63.6 x [tex]10^3[/tex] V = 1.02 x [tex]10^{-15}[/tex] J

The shortest wavelength of radiation emitted by the tungsten target is then determined by the energy of the electrons using the equation:

lambda = hc / E

where **lambda** is the wavelength of the radiation, h is the Planck constant (6.63 x [tex]10^{-34}[/tex] J s), c is the speed of light (2.998 x [tex]10^8[/tex] m/s), and E is the energy of the electrons.

Substituting the values into this equation, we get:

lambda = 6.63 x [tex]10^{-34}[/tex] J s × 2.998 x [tex]10^8[/tex] m/s / 1.02 x [tex]10^{-15}[/tex] J = 1.87 x [tex]10^{-7}[/tex] m

Converting this to nanometers (nm), we get:

lambda (nm) = 1.87 x [tex]10^{-7}[/tex] m * [tex]10^{9}[/tex] nm/m = 187 nm.

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an object is placed to the left of a concave mirror, beyond its focal point. in which direction will the image move when the object is moved farther to the left?

### Answers

The item must be positioned outside of the mirror's center of curvature. Since the focal point is closer to the **mirror**, the item must be farther away.

Where does the image originate when an object is positioned at the concave mirror's focal point?

when the **concave **mirror's object focus is on the object. As a result, the image is actual, inverted, and much amplified because it is generated at infinity.

What happens if you position anything precisely at a concave mirror's focus point?

No image is created when the object is at the **focal point**. The mirror will reflect light beams from the same spot on the object, preventing convergence or divergence.

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The gravitational acceleration on earth is 9.8 m/s2. what is the weight of a car on earth (to the nearest whole number) if it has a mass of 1360 kg?

### Answers

**Answer:**

13328 Newtons

**Explanation:**

Definition of Weight

[tex]W=mg[/tex]

We are given

[tex]m=1360[/tex]

[tex]g=9.8[/tex]

So the weight is equal to

[tex]W=1360*9.8[/tex]

[tex]W=13328[/tex]

on the line between the speakers there are points where maximum sound intensity occurs. what is the distance of the nearest point from speaker a?

### Answers

The **distance **of the nearest point from speaker A is half of the distance between the speakers.

This is due to** constructive interference**, which is the phenomenon that occurs when two sound waves of equal frequency combine to produce a wave of greater** amplitude**. When two sound waves of equal frequency and amplitude meet in phase, the sound pressure of the combined wave is the sum of the two individual **waves**. When this occurs, the pressure at the point of constructive interference is twice that of the individual waves and the **intensity** is four times the intensity of each of the individual waves. The equation for the distance between the points of maximum sound intensity is 2d = λ/2, where λ is the **wavelength **of the sound wave. The wavelength of a sound wave is related to its frequency by λ = v/f, where v is the speed of sound and f is the frequency of the** sound**. The speed of sound is approximately 340 m/s in air, so if the frequency is known, the equation can be used to calculate the distance between the** speakers**.

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in a loop traverse the sum of the interior angles should be equal to what value if there are 8 stations?

### Answers

In a loop **traverse** the sum of the interior angles should be equal to 12, if it has 8 stations.

Traverse Surveying is a popular **surveying** method.

Traversing is a type of survey in which several connected survey lines form a skeleton, and the directions and lengths of the survey lines are measured using a **protractor** and a tape or chain.

Surveying is basically of two types:

**Closed traverse**: When the lines form a circuit that ends at the starting point, it is called a closed traverse.**Open Traverse**: When the lines forming a circuit end somewhere other than the starting point, it is said to be an open traverse.

The errors in the surveying can be found out by angles induced in transverse.

The sum of the measured internal angles should be equal to **(2N-4)**, where N=number of sides of the traverse.

Number of stations = N = 8

Sum of the interior angles = (2N - 4)

Sum = (2*8 - 4)

Sum = 12

The **sum** of the interior angles should be equal to **12**.

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a projectile motion is launched at a velocity of 125 m/s at an angle of 30. a building is 200m away at what height above the ground will the projectile strike the building at

### Answers

°C, or 45 °F. The maximum range of a projectile without** air resistance **occurs when it is thrown at a 45-degree angle.

Describe the mechanism of air resistance.

Translation: A pressure that is brought on by air called air resistance. An object **travelling** through the air experiences the force in the opposite direction. A sports vehicle with a **streamlined** form will face less air resistance than a truck with a flat front, enabling the latter to travel faster.

Why is there air resistance?

The object's **speed**, area, and shape all affect how much air resistance it experiences. The resistance of the air is affected by altitude, temperature, and **humidity**. Higher speed and a larger area result in greater resistance.

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in projectile motion why does an object have a nonzero instantaneous acceleration stop rising and falling

### Answers

An object have a nonzero instantaneous **acceleration** during** projectile motion **is because the gravitational force acting on the body is in the downward direction.

For a projectile motion, the **gravitational force** following up on the body is in the descending bearing. Hence, the body in a shot movement has speed increase because of **gravity** 9.8 m/s2. It should be noticed that no power is following up on the body in the shot movement in the flat heading.

At the point when a molecule is tossed diagonally close to the world's surface, it moves along a bended way under consistent **speed **increase coordinated towards the focal point of the earth (we expect that the molecule stays near the world's surface). The way of such a molecule is known as a shot, and the movement is called shot movement.

In a projectile motion, there are two synchronous free **rectilinear **movements:

Along the x-pivot: uniform speed, answerable for the flat (forward) movement of the molecule.

Along the y-pivot: uniform speed increase, answerable for the **vertical **(downwards) movement of the molecule.

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if jed and kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (indicate the direction with the sign of your answer.)

### Answers

The final **velocity **of the two joined objects after the** collision **would be 0 m/s (0)

This can be obtained by using the one-dimensional **conservation of momentum** equation, p = m1v1 + m2v2, where m1 and m2 are the **masses **of the two objects, and v1 and v2 are their initial velocities. Since the two objects are joined after the collision, the final** velocities** of both objects are the same. Therefore, if we set v2 to equal the negative of v1 and solve for v1, we get 0 m/s. This shows that the final velocity of the two joined objects is 0 m/s since the momentum of the system is conserved.

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what is the centripetal acceleration of an object on the earth's equator pwomg tp the rotation of the earth

### Answers

**Answer:**

3.39 cm/sec^2

**Explanation:**

according to the nebular theory of solar system formation, why were solid planetesimals able to grow larger in the outer solar system than in the inner solar system?

### Answers

According to the **Nebular Theory of Solar System Function,** the solid planetesimals are able to grow larger in the outer solar system than in the **inner solar system** because only metal and rock could condense in the inner solar system, while ice also condensed in the **outer solar system.**

**Terrestrial planets** formed where only dense materials could **condense, **which doesn't apply for Jovian planets. That's why they're rocky and small while the ones that couldn't condense **dense** materials are large and gaseous and found further away from the star.

The types of **objects **found within the solar system provide significant clues and evidence to support the Nebular Theory. First; the types of Planets and their distributions: with the Rocky planets being close to the Sun, and **Gas Giants planets** being far from the Sun, Dwarf Planets or **Plutoids**, a class of Dwarf planets, are found far from the Sun.

Next, Comets, asteroids, and meteorites recovered on **Earth **also provide a number of clues and evidence of Nebular-type development. And the **motions **of most solar system objects orbit and rotate in an organized fashion.

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Iolation, no job ecurity, work overload , harament and bullying are example of factor that can lead to

### Answers

Job stress caused by **Isolation**, a lack of job security, work overload, harassment, and bullying .Even a very challenging workout might cause this kind of tension.

Which of the subsequent describes eustress?

Smaller difficulties: Eustress might take the form of the thrill of a roller-coaster ride, a spooky movie, or a fun challenge. Even a very challenging workout might cause this kind of **tension**. fresh encounters: Traveling can be stressful as well.

What are some instances of typical stress?

The majority of normative stresses are predictable and expected and include difficulties that most people face (e.g., giving birth, marriage or retirement). Contrarily, non-normative stressors include unforeseen life occurrences that do not occur frequently during the life cycle.

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4. calculate the height of the coulomb barrier for the head-on collision of two deuterons. take the effective radius of a deuteron to be 2.1 fm.

### Answers

As a result, the potential barrier of the **two-deuteron system **is 360 keV high.

What is the theoretical barrier height for a head-on collision of two deuterons ?

Let d be the distance between the centers of two deuterons.

The formula for the distance d between two deuterons is d=radius of one deuteron plus radius of two deuterons.

Fill in the blanks in the above equation.

d=2× 10 −15 +2× 10 −15 =4× 10 −15 m

A **deuteron nucleus** has a charge of e=1.6 10 19 C.

The two-deuteron system's potential energy is provided by,

V= e 2 4π ε ° d

In this case, 0 represents the permittivity of free space.

Substituting the numbers in the preceding equation yields:

V= e 2 4π ε ° d = ( 1.6× 10 −19 )

2 4×π×8.85× 10 −12 ×4× 10 −15 =360 keV

As a result, the **potential barrier **of the two-deuteron system is 360 keV high.

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how much work is it to push a box (mass 200 kg) up an incline (angle 20 degrees with the horizontal) that is 8.6 meters long, if the coefficient of kinetic friction between the box and the incline is 0.6?

### Answers

**Answer:**

15284.35 Joules

**Explanation:**

Here is an equation we can use.

Work + Initial PE + Initial KE = Final PE + Final KE + heat lost

[tex]W+mgh_i+\frac{1}{2}mv_i^{2} =mgh_f+\frac{1}{2}mv_f^{2}+F_Fd[/tex]

Solving for W gives us.

[tex]W=-(mgh_i)-(\frac{1}{2}mv_i^{2}) +mgh_f+\frac{1}{2}mv_f^{2}+F_Fd[/tex]

In this case we can assume the initial height is 0. So there is no Initial PE.

We can assume the box started at 0 m/s. So there is no Initial KE

The box gained height as it moved up the incline. So there is Final PE.

We can assume the box moved at a constant speed. There was no acceleration on the box. So there is no Final KE.

[tex]F_F=F_N*u_k[/tex]

[tex]F_N=mgcos(B)[/tex]

[tex]F_F=mgcos(B)*u_k[/tex]

[tex]W=mgh_f+F_Fd[/tex]

[tex]W=mgh_f+mgcos(B)*u_k*d[/tex]

[tex]h_f=d*sin(B)[/tex]

[tex]W=m*g*d*sin(B)+m*g*cos(B)*u_k*d[/tex]

Lets solve for [tex]W[/tex]

We are given

[tex]m=200[/tex]

[tex]g=9.81[/tex]

[tex]B=20[/tex]

[tex]u_k=0.6[/tex]

[tex]d=8.6[/tex]

Replace the variables with our given numbers.

[tex]W=200*9.81*8.6*sin(20)+200*9.81*cos(20)*0.6*8.6[/tex]

[tex]W=15284.35[/tex]

A pair of parallel lines is cut by a transversal. which group of angles measures 43°? a. angles 1, 2, 3 b. angles 2, 5, 4 c. angles 1, 3, 5 d. angles 5, 6, 7 e. angles 3, 4, 6

### Answers

A transversal divides two **parallel lines**. Angles 1, 3, and 5 make comprise the 43° group of angles.

Is two lines are cut by a transversal?

Each set of alternate internal angles created by a transversal when two parallel lines are sliced are equal. Each pair of internal angles on the same side of the transversal are **supplementary**, or they add up to 180 degrees, if two parallel lines are sliced by it.

If the corresponding angles at the intersection of any two lines are equal, the intersection is said to be a parallel one. If the opposing interior angles of any two lines intersected by a transversal are equal, the lines are said to be parallel.

Given : A pair of parallel lines is cut by a transversal.

∠1 + 137 ° = 180° ( **Linear pair angle** ) .

On subtracting both sides by 137

∠1 = 180 -137 .

∠1 = 43°.

Then, ∠1 = ∠3 ( Vertically opposite angles)

So, ∠3 = 43°.

Now, ∠3 = ∠5 ( Alternate interior angle ) .

So, ∠5 = 43°.

group of angles measures 43° = angle 1 , 3 , 5.

Therefore, the correct answer is option C) angles 1, 3, 5.

The complete question is:

A pair of parallel lines is cut by a transversal. Which group of angles measures 43°?

A. angles 1, 2, 3

B. angles 2, 5, 4

C. angles 1, 3, 5

D. angles 5, 6, 7

E. angles 3, 4, 6

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Question 2

2. There is 100g mass on your desk to which you apply a 5N force. What is the acceleration

of the 100g mass? (Ignore friction)

### Answers

Taking into account the Newton's second law, the **acceleration of the 100 g mass **is 50 m/s².

Newton's second law

Newton's second law states that this force will change the speed of an object because the acceleration and/or direction will change.

So, Newton's second law defines the **relationship** between **force and acceleration** mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object:

F= m×a

where:

F = Force [N]m = Mass [kg]a = Acceleration [m/s²]

Acceleration in this case

In this case, you know:

F= 5 Nm= 100 g= 0.1 kg (being 1000 g= 1 kg)a= ?

Replacing in **Newton's second law**:

5 N= 0.1 kg× a

Solving:

a= 5 N÷ 0.1 kg

*a= 50 m/s²*

Finally, the **acceleration **is 50 m/s².

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he figure shows two unequal point charges, q and O. of opposite sign. Charge Q has greater magnitude charge q. In which of the regions X, Y, Z will there be a point at which the net electric field due to these two charges is zero?

A) only regions X and Z

B) only region X

C) only region Y

D) only region Z

E) all three regions

### Answers

He figure shows** two unequal point **charges, q and O. of opposite sign. Charge Q has greater** magnitude charge** q. In the regions X, Y, Z will there be a point at the net electric field due to these two charges is zero only region X .

**What is** **magnitude charge?**

The charge of the** electron is equivalent to the magnitude** of the elementry charge ( e ) but bearing a negative sign. Since the value of elementry charge ( e) is roughly =1. 6×10−19 Hence charge of electron is =−1. 6×10−19 so from here we can see the Magnitude of** electronic charge** is ∣e∣=1.

We can use the equation E = k | Q | r 2 E = k | Q | r 2 to find the magnitude of the electric field. The direction of the electric field is determined by the sign of the charge, which is negative in this case. E = k | Q | r 2 = ( 8.99 × 10 9 N ⋅ m 2 /C 2 ) | − 1.5 × 10 − 9 C | ( 0.035 m ) 2 = 1.1 × 10 4 N/C.electric charge comes in two types, which we choose to call positive charge and negative charge. This is the magnitude of the force which each charge exerts on the other charge .

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An airplane travels 1200 miles from annapolis to dallas in 4. 8 hours, going against the wind. The return trip is with the wind, and takes only 4 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

### Answers

**Aircraft speed** in a windless environment is 276 mph. The** **wind is blowing at 25 mph.

Calculation:

Since distance and time have a **relationship **that represents speed, the speed against the wind;

**Speed **=1200/4.8

250 kilometers **per hour **is the speed

So, let x represent the wind speed.

Let y be the **airborne **object's windless speed.

y-x=250 (1) (1)

The speed now with the wind is as **follows**: y+x=300 x=300-y 1200/4=300 miles per hour.

So, to solve the **system of equations**, utilize the substitution approach. Replace (1) with (2) to get:

y-(300-y)=250\sy-300+y=250\s2y=550\sy=550/2\sy=275mph

**knowing **the plane's value in a windless environment. To determine the wind speed, replace y in (2):

x=300-275\sy=25mph

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one end of a string is attached to a ball, with the other end held by a student such that the ball is swung in a horizontal circular path of radius rr at a constant tangential speed. at a later time, the tension force exerted on the ball remains constant, but the length of the string is decreased to r4r4. what is the new tangential speed of the ball

### Answers

When a student holds the other end of a string while holding a ball, the ball is swung in a horizontal circular pattern at a **speed **that is half that of the initial pace.

How fast is the ball moving tangentially?

Tangential velocity is calculated by dividing the circle's circumference by the time needed for one full rotation, or 2*pi*r/t.

The rotating object's angular **acceleration **and angular velocity are related by the equation V = w * r, where w (omega) is the angular acceleration and r is the diameter of the circle.

What is a good illustration of tangential speed?

A point with angular **velocity **possesses tangential velocity, which is its present speed. Imagine a tiny item that is attached to a string, and that it's revolving around a stationary point. The object's maximum distance is the length of the string, therefore if it moves continuously, its motion will be circular.

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express or implied knowledge of a fact is known as...? notice actual notice recordation constructive notice

### Answers

"Express or implied knowledge of a fact is known as **actual notice**."

A person is said to have received an actual notice of a fact when they have direct, express **knowledge** of it or receive an indication of it.

Actual notice is when another party interested in the transaction expressly or formally notifies another party of a specific fact related to the transaction.

Definite knowledge, it should not be hearsay or **rumours**. The notice must be written in a way that makes it reasonable to assume that the recipient will take it seriously. It must be the result of a formal communication and not a casual conversation between individuals.

It is established law that a person is not required to heed speculative rumours or assertions made by complete strangers unless they are given by a party engaged in the **transaction**. A notice must originate from certain parties involved in the transaction for it to be enforceable.

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multi choice

15) A coiled spring used to help a door close has mechanical energy when the door is open.

### Answers

The coiled spring has** elastic potential energy** when the door is open.

What kind of power is employed to open doors?

You have** chemical potential energy** (energy stored within you), and the motion of pushing the door with your hands had kinetic energy as well (energy in the motion of your hands). Your kinetic and potential energy were converted into **mechanical energy** when you pushed the door, which resulted in work being done (door opened).

Springs are constructed from substances like spring steel, which, when compressed, stretched, or twisted, reverts to its original shape. Elastic potential energy, which the spring stores when it is bent from its free state and then releases when the spring is unwound, is stored in the deformed state.

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a satellite of mass m has an orbital period t when it is in a circular orbit of radius r around the earth. if the satellite instead had mass 4m, its orbital period would be

### Answers

The **orbital period **is independent of the satellite mass, which means that every satellite orbiting the earth at a radius R has an orbital period A regardless of its mass so option option -A is correct.

What is orbital period?

The duration of one orbit around another **astronomical object **is known as the orbital period (also known as the revolution period). It typically refers to bodies like planets or asteroids that orbit the Sun, moons that orbit other planets, exoplanets that orbit other stars, or binary stars.

According to** Kepler's third law**, a satellite's orbital period (T) depends on the mass and radius of the object it orbits:

T = 2π[tex]R^{3/2}[/tex]/[tex]\sqrt{GM}[/tex]

As a result, the orbital period is independent of the satellite's mass, which means that regardless of mass, every satellite orbiting the earth at a radius R has an orbital period A.

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what is the moment of inertia about the cm? what is the moment of inertia about an axis through the pivot?

### Answers

The **moment of inertia**,I of this assembly about the axis through which it is pivoted is [tex]I=x^2(m_1+m_2+\frac{m_r}{3})[/tex]

From figure,

we can observe that the data,

[tex]m_1[/tex] = sphere 1's mass

[tex]m_2[/tex] = sphere 2's mass

[tex]m_r[/tex] = the weight of the rod

x= the distance between sphere 1 and pivot

x= the distance between sphere 2 and pivot

2x = total length of the rod

We must determine the expression of the sphere's moment of inertia and the expression of the rod's moment of inertia.

The formula for moment of inertia of sphere is expressed as,

[tex]I=mr^2...i[/tex]

Where, m=**mass** of sphere

r=**distance** between sphere and pivot

The formula for moment of inertia of rod can be expressed as ,

[tex]I=\frac{ml^2}{12}....ii[/tex]

Where,

m=mass of rod

l=**length** of the rod

Substituting the values of sphere 1 and sphere 2 in the eq. i,

[tex]I_1=m_1x^2\\\\I_2=m_2x^2[/tex]

substitute the values of rod in the moment of inertia in eq.ii

[tex]I_r=\frac{m_r(2x)^2}{12}\\\\I_r=\frac{4m_rx^2}{12}\\\\I_r=\frac{m_rx^2}{3}[/tex]

Now, the total **moment of inertia** is the sum of all the inertias of spheres and the rod,

[tex]I=I_1+I_2+I_r\\\\I=m_1x^2+m_2x^2+\frac{m_rx^2}{3}\\\\I=x^2(m_1+m_2+\frac{m_r}{3})[/tex]

Hence, the moment of inertia of the whole assembly is [tex]I=x^2(m_1+m_2+\frac{m_r}{3})[/tex]

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Your question is incomplete, here is the complete question

what is the moment of inertia i of this assembly about the axis through which it is pivoted? express the moment of inertia in terms of mr , m1 , m2 , and x . keep in mind that the length of the rod is 2x , not x .

Making sure that there are no gaps that will allow the heat to escape a

answers:

radiation

convection

conduction

### Answers

Conduction is a way for **heated **temperatures to lose heat. The body can rapidly lose heat when swimming or sitting in cool or cold water, which increases the risk of **hypothermia**. Thus, option **C **is correct.

What conduction, no gaps that allow the heat to escape?

Because they are poor **conductors**, insulating materials limit heat loss through conduction. Additionally, the **material **stops air from moving about inside the chamber, hence minimizing convectional heat loss. Installing loft insulation will help to prevent heat loss via the roof.

Therefore, **Insulators **should be placed between the patient and good conductors to reduce conduction **heat **loss. Conduction, no gaps that will allow the heat to **escape**.

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A student is completing an experiment to see how using different metals in a battery will affect the flow of electrons and the

voltage of the battery. The table below shows the electron affinity of four metals.

if paired with silver, which metal would result in no flor of electric charges?

### Answers

In order to strengthen the battery, we can alter it to include new metals with even greater differences in **electronegativity**. Electrons will then flow from Zinc to Lithium.

Three electron-related facts

**Electrons **in orbit that are negatively charged encircle the outside of the nucleus. Because they rotate so swiftly, it can be difficult for scientists to keep an eye on them. They are the smallest particles in an atom and therefore are drawn to the **positive charges **of protons; one proton can carry 2000 of them.

Give an example of the an electron.

An electron, that has a **negative charge**, is the smallest and least substantial part of an atom. Both the protons and electrons are equal in number in a neutral atom. For instance, a hydrogen atom only has one proton or one electron. While the **atomic nucleus **has 92 protons, which means 92 electrons.

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if the mass is pulled to the right and then released, how long will it take for the mass to reach the leftmost point of its motion

### Answers

if the **mass **is pulled to the right and then released, how long will it take for the mass to reach the leftmost point of its motion is [tex]s \theta I \mathrm{sec}[/tex].

**What is mass?**

A body's mass is an** inherent quality**. Before the discovery of the atom and the field of particle physics, it was **conventionally **thought to be related to the amount of matter in a** physical body**.

We can see

[tex]- $x_{\text {man }}$[/tex] is right meat position

[tex]$-x_{\text {mar }}$[/tex] is left most position.

If mass is released at rightmost petition then it will come again to rightmost in two sec.

But it will be at leftmost position in[tex]$T / 2$[/tex] time de. I sec

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